vault backup: 2025-09-18 12:43:06

education/math/MATH1220 (calc II)/Integration with Trig Identities.md

@@ -54,4 +54,14 @@ $$ \theta = \arctan(\frac{x}{2}) $$
 7. Rewriting the equation with $\theta$ in terms of x, we get:
 $$ \frac{3}{2}\arctan(\frac{x}{2}) + C$$
 This means that:
-$$ \int\frac{3}{4+x^2}dx = \frac{3}{2}\arctan(\frac{x}{2}) + C $$
+$$ \int\frac{3}{4+x^2}dx = \frac{3}{2}\arctan(\frac{x}{2}) + C $$
+
+# A VERY LARGE LIST OF TRIG IDENTITIES FOR CALCULUS
+
+| non calc identities<br>              |
+| ------------------------------------ |
+| $\csc(x) = \dfrac{1}{sin(x)}$        |
+| $\sec(x) = \dfrac{1}{\cos(x)}$       |
+| $\cot(x) = \dfrac{1}{\tan(x)}$       |
+| $\tan(x) = \dfrac{\sin(x)}{\cos(x)}$ |
+| $\sin^2(x) + \cos^2(x) = 1$          |