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education/math/MATH1060 (trig)/Graphing.md
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education/math/MATH1060 (trig)/Graphing.md
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![A graph of sine and cosine](./assets/graphsincos.png)
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Given the above graph:
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- At the origin, $sin(x) = 0$ and $cos(x) = 1$
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- A full wavelength takes $2\pi$
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# Manipulation
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| Formula | Movement |
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| ------------------ | -------- |
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| $ y = cos(x) - 1 $ | |
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@ -65,4 +65,6 @@ Applying the exponent gives us $\frac{49}{625}$, so we can do this:
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$$ \frac{625}{625} - \frac{49}{625} = \frac{576}{625} = sin^2\theta $$
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$$ \frac{625}{625} - \frac{49}{625} = \frac{576}{625} = sin^2\theta $$
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Getting rid of the exponent:
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Getting rid of the exponent:
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$$ \sqrt{\frac{576}{625}} = $$
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$$ \sqrt{\frac{576}{625}} = \frac{24}{25} = sin\theta $$
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From there, you can find the rest of the identities fairly easily.
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education/math/MATH1060 (trig)/assets/graphsincos.png
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education/math/MATH1060 (trig)/assets/graphsincos.png
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