vault backup: 2025-03-25 09:41:37
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@ -58,4 +58,6 @@ $f(x_i)$ is the *height* of each sub-interval, and $\Delta x$ is the change in t
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Relevant formula:
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$$ \sum_{i = 1}^n = \dfrac{(n)(n + 1)}{2} $$
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1. $
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1. $\int_0^1 5x \space dx = \lim_{n \to \infty} \sum_{i=1}^n 5(x_i) * \Delta x$
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2. $= \lim_{n \to \infty} \sum_{i=1}^n 5(\frac{1}{n} \cdot i) \cdot \frac{1}{n}$
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3. $
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