vault backup: 2024-09-23 11:25:52

education/math/MATH1060 (trig)/Identities.md

@@ -44,4 +44,11 @@ If $sec\theta = -\frac{25}{7}$ and $0 < \theta < \pi$, find the values of the ot
 
 Using the trig identity $1 + tan^2\theta = cot^2\theta$, we can do this:
 $$ 1 + tan^2\theta = (-\frac{25}{7})^2 $$
-$25^2
+Shuffling things around, we get this:
+$$ tan^2\theta = \frac{625}{49} - 1 $$
+
+Performing that subtraction gives us this:
+$$ \frac{625}{49} - \frac{49}{49} = \frac{576}{49} = tan^2\theta $$
+You can get rid of the exponent:
+
+$$ \frac{576}{49}