From 481b58fe54a3f3068197d08517c38035789b07ae Mon Sep 17 00:00:00 2001
From: zleyyij <75810274+zleyyij@users.noreply.github.com>
Date: Mon, 23 Sep 2024 11:25:52 -0600
Subject: [PATCH] vault backup: 2024-09-23 11:25:52

---
 education/math/MATH1060 (trig)/Identities.md | 9 ++++++++-
 1 file changed, 8 insertions(+), 1 deletion(-)

diff --git a/education/math/MATH1060 (trig)/Identities.md b/education/math/MATH1060 (trig)/Identities.md
index 803e267..b11332e 100644
--- a/education/math/MATH1060 (trig)/Identities.md	
+++ b/education/math/MATH1060 (trig)/Identities.md	
@@ -44,4 +44,11 @@ If $sec\theta = -\frac{25}{7}$ and $0 < \theta < \pi$, find the values of the ot
 
 Using the trig identity $1 + tan^2\theta = cot^2\theta$, we can do this:
 $$ 1 + tan^2\theta = (-\frac{25}{7})^2 $$
-$25^2
\ No newline at end of file
+Shuffling things around, we get this:
+$$ tan^2\theta = \frac{625}{49} - 1 $$
+
+Performing that subtraction gives us this:
+$$ \frac{625}{49} - \frac{49}{49} = \frac{576}{49} = tan^2\theta $$
+You can get rid of the exponent:
+
+$$ \frac{576}{49} 
\ No newline at end of file