Files
notes/education/physics/PHYS2210/Unit 1.md
2025-09-03 13:47:38 -06:00

1.4 KiB

Motion in a straight line is one dimensional.

Kinematics or the physics of motion has 4 noteworthy parameters: time (t), position (x), velocity (v), and acceleration (a).

Kinematic problems have a start and end of motion.

Displacement

Displacement is calculated with the formula:

\Delta x = \text{x-value of final position} - \text{x-value of initial posiion}

Velocity

Average velocity over a time interval \Delta t is defined to be: the displacement (net change in position), divided by the time taken.

\bar{v} = \dfrac{\text{final position-initial position}}{\text{final time - initial time}} = \dfrac{x_2 - x_1}{t_2 - t_1} = \dfrac{\Delta x}{\Delta t}

Speed (m/s) is defined to be the total distance traveled divided by the time taken. Speed and velocity are not the same.

v_{\text{instant}} = v = \lim_{\Delta t \to 0}\frac{\Delta x}{\Delta t} = \frac{dx}{dt}
  • x(t) -> position as a function of time
  • v(t) -> slope of position-vs-time (derivative of x(t))
  • a(t) -> slope of velocity-vs-time (derivative of v(t))

Acceleration

To find the instantaneous acceleration, we can apply the formula:

a_{\text{instant}} = a = \frac{dv}{dt} = \frac{d}{dt} \frac{dx}{dt} = \frac{d^2x}{dt^2}

Equations of Motion for Constant Acceleration

  1. v = v_0 + at
  2. x = x_0 + \frac{1}{2}(v_0 + v)t
  3. x = x_0 + v_0 t + \frac{1}{2} a t^2
  4. v^2 = v_0^2 + 2a(x - x_0)