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Maximum/Minimum
A function f has an absolute maximum at c if f(c) >= f(x). We call f(c) the maximum value of f.
The absolute maximum is the largest possible output value for a function.
A function f has an absolute minimum at c if f(c) <= f(x). f(c) is the absolute minimum value of f.
The absolute minimum is the smallest possible output value for a function.
- Where the derivative of a function is zero, there is either a peak or a trough.
Critical Numbers
A number is considered critical if the output of a function exists and \dfrac{d}{dx} is zero or undefined.
Local Max/Min
A local max/min is a peak or trough at any point along the graph.
Extreme Value Theorem
If f is a continuous function in a closed interval [a, b], then f achieves both an absolute maximum and an absolute minimum in [a, b]. Furthermore, the absolute extrema occur at a or at b or at a critical number between a and b.
Examples
Find the absolute maximum and absolute minimum of the function
f(x) = x^2 -3x + 2on the closed interval[0, 2]:
x=0andx=2are both critical numbers because they are endpoints. Endpoints are always critical numbers because\dfrac{d}{dx}is undefined.\dfrac{d}{dx} x^2 -3x + 2 = 2x -3- Setting the derivative to zero,
0 = 2x - 3 - Solving for x, we get
x = \dfrac{3}{2}. Three halves is a critical number becausef'(\dfrac{3}{2})is0. - Now check the outputs for all critical numbers (
f(x)atx = \{0, 2, \dfrac{3}{2}\}) f(0) = 0^2 -3(0) + 2 = 2f(2) = 2^2 - 3(2) + 2) = 0f(\dfrac{3}{2}) = (\dfrac{3}{2})^2 - 3(\dfrac{3}{2}) + 2 = -\dfrac{1}{4}- The minimum is the lowest of the three, so it's
-\dfrac{1}{4}and it occurs atx = \dfrac{3}{2} - The maximum is the highest of the three, so it's
2atx = 0.
Find the absolute maximum and absolute minimum of the function
h(x) = x + 2cos(x)on the closed interval[0, \pi].
x = 0andx = \piare both critical numbers because they are endpoints. Endpoints are critical because\dfrac{d}{dx}is undefined.