2.1 KiB
Maximum/Minimum
A function f
has an absolute maximum at c
if f(c) >= f(x)
. We call f(c)
the maximum value of f
.
The absolute maximum is the largest possible output value for a function.
A function f
has an absolute minimum at c
if f(c) <= f(x)
. f(c)
is the absolute minimum value of f
.
The absolute minimum is the smallest possible output value for a function.
- Where the derivative of a function is zero, there is either a peak or a trough.
Critical Numbers
A number is considered critical if the output of a function exists and \dfrac{d}{dx}
is zero or undefined.
Local Max/Min
A local max/min is a peak or trough at any point along the graph.
Extreme Value Theorem
If f
is a continuous function in a closed interval [a, b]
, then f
achieves both an absolute maximum and an absolute minimum in [a, b]
. Furthermore, the absolute extrema occur at a
or at b
or at a critical number between a
and b
.
Examples
Find the absolute maximum and absolute minimum of the function
f(x) = x^2 -3x + 2
on the closed interval[0, 2]
:
x=0
andx=2
are both critical numbers because they are endpoints. Endpoints are always critical numbers because\dfrac{d}{dx}
is undefined.\dfrac{d}{dx} x^2 -3x + 2 = 2x -3
- Setting the derivative to zero,
0 = 2x - 3
- Solving for x, we get
x = \dfrac{3}{2}
. Three halves is a critical number becausef'(\dfrac{3}{2})
is0
. - Now check the outputs for all critical numbers (
f(x)
atx = \{0, 2, \dfrac{3}{2}\}
) f(0) = 0^2 -3(0) + 2 = 2
f(2) = 2^2 - 3(2) + 2) = 0
f(\dfrac{3}{2}) = (\dfrac{3}{2})^2 - 3(\dfrac{3}{2}) + 2 = -\dfrac{1}{4}
- The minimum is the lowest of the three, so it's
-\dfrac{1}{4}
and it occurs atx = \dfrac{3}{2}
- The maximum is the highest of the three, so it's
2
atx = 0
.
Find the absolute maximum and absolute minimum of the function
h(x) = x + 2cos(x)
on the closed interval[0, \pi]
.
x = 0
andx = \pi
are both critical numbers because they are endpoints. Endpoints are critical because\dfrac{d}{dx}
is undefined.