2.9 KiB
2.9 KiB
The below integration makes use of the following trig identities:
- The Pythagorean identity:
\sin^2(x) + \cos^2(x) = 1
- The derivative of sine:
\frac{d}{dx}sin(x) = cos(x)
- The derivative of cosine:
\dfrac{d}{dx} \cos(x) = -\sin(x)
- Half angle cosine identity:
\cos^2(x) = \frac{1}{2}(1 + \cos(2x))
- Half angle sine identity:
\sin^2(x) = \frac{1}{2}(1 - \cos(2x))
tan^2(x) + 1 = sec^2(x)
\dfrac{d}{dx}(\tan(x)) = \sec^2(x) \Rightarrow \int \sec^2(x)dx = \tan(x) + C
\dfrac{d}{dx}(\sec x) = \sec(x)\tan(x) \Rightarrow \int\sec(x)\tan(x) dx = \sec(x) + C
Examples
Evaluate the integral
\int\sin^5(x)dx
- With trig identities, it's common to work backwards with u-sub. In the above example, we can convert the equation into simpler cosine functions by setting
du
to-\sin(x)dx
. This means thatu
is equal tocos(x)
.
\int\sin^4(x)\sin(x)dx
- Rewrite
sin^4(x)
to be(\sin^2(x))^2
to take advantage of the trig identity1 - \cos^2(x) = \sin^2(x)
\int(\sin^2x)^2 \sin(x)dx
- Apply the above trig identity and substitute
u
:
\int(1 - u^2)^2 (-du)
- Foil out and move negative out of integral:
-\int(1 - 2u^2 + u^4)du
- Take advantage of the distributive property of integrals:
- (u - \frac{2}{3}u^3 + \frac{1}{5}u^5) + C
- Substituting
\cos(x)
back in foru
, we get the evaluated (but not entirely simplified) integral:
-(\cos(x)- \frac{2}{3}\cos^3x + \frac{1}{5}\cos^5x)
Trigonometric Substitutions
Trigonometric substitution is useful for equations containing \sqrt{a^2 + x^2}
or a^2 + x^2
, where a
is any constant. It removes any addition or subtraction.
The general process involves the use of a trig identity and multiplying everything in that identity by a constant.
Consider the identity:
1 + \tan^2(\theta) = \sec^2(\theta)
Multiplying both sides of the identity by a^2
, we get:
a^2 + a^2\tan^2(\theta) = a^2\sec^2(\theta)
This enables us to make use of substitution to simplify many integrals.
x = a\tan \theta
dx = a \sec^2\theta d\theta
- for
-\frac{\pi}{2} < \theta < \frac{\pi}{2}
Examples
Evaluate the integral
\int\frac{3}{4+x^2}dx
- Move the constant coefficient out of the integral:
\int \frac{3}{4+x^2}dx = 3\int \frac{1}{4 + x^2}dx
- Let
x = 2tan\theta
anddx = (2sec^2\theta d\theta)
, substitute accordingly
= 3\int\frac{1}{4 + 4\tan^2\theta}(2\sec^2\theta)d\theta
- Factor
4
out in the denominator
= 3\int\frac{1}{4(1 + \tan^2\theta)}(2\sec^2\theta)d\theta
- Considering the identity
1 + \tan^2 \theta = \sec^2 \theta
= 3\int\frac{1}{4(\sec^2\theta)}(2\sec^2\theta)d\theta
\sec^2\theta
is present in the numerator and the denominator, so we can cancel those out. This means that:
3\int\frac{2}{4}d\theta = \frac{3}{2} \theta + C
- At this point, we want to determine what
\theta
is equal to relative tox
.- Look back to step 2 we defined
x = 2\tan\theta
- Moving
2
to the other side to,
- Look back to step 2 we defined