556 B
556 B
Examples
Given the below problem, the two equations can't simplified further. So to find the domain, you need to look for the domain where they're both valid, eg [-2, 5]
.
\sqrt{x+2} + \sqrt{5-x}
The below example has a domain of [-2, 5)
because x
cannot equal 0 for the denominator
\frac{\sqrt{x+2}}{\sqrt{5-x}}
Assuming f(x) = \frac{2}{x-3}
, and g(x) = \frac{5}{x+1}
, (f\circ g)(x)
, you can find the domain by finding the domain for each function, then fully expanding it and seeing if any more unreachable numbers are included