996 B
Long division
\frac{6x^2-x-2}{2x+1} Given the above problem, you'd first start by figuring out what you'd multiple the largest exponent in the denominator (2x) by, to equal the largest number in the numerator (6x^2). In this case, that number is 3x. You'd then multiple the entire denominator by that number, giving you 6x^2 + 3x. 3x would then be part of your solution, and you'd subtract 6x^2+3x from 6x^2-x-2 to give you -4x-2. The process is then repeated with -4x-2, figuring out what you'd multiply to cancel it out, then adding that to your solution. This is repeated until you can't anymore. This is your remainder, and can be written as \frac{r}{2x+1}, where r is your remainder, and 2x + 1 is the denominator in the original equation.
Synthetic Division
This is a slightly more efficient method of devision that's valid when the denominator is in the form of x \pm n, or x plus or minus a number.