2.7 KiB
Trigonometric Identities
All of the following only apply when the denominator is not equal to zero.
tan \theta = \frac{y}{x}
Because the following are inverses of their counterparts, you only need to remember the equivalents for sin
, cos
, and tan
, then just find the inverse by taking 1/v
.
Base Identity | Inverse Identity | Alternate Identities | Alternate Inverse Identities |
---|---|---|---|
sin\theta = y
|
csc\theta = \frac{1}{y}
|
csc\theta = \frac{1}{sin\theta}
|
|
cos\theta = x
|
sec \theta = \frac{1}{x}
|
sec\theta = \frac{1}{cos\theta}
|
|
tan\theta = \frac{y}{x}
|
cot\theta = \frac{x}{y}
|
tan\theta = \frac{sin\theta}{cos\theta}
|
cot\theta = \frac{1}{tan\theta} = \frac{cos\theta}{sin{\theta}}
|
cot \theta = \frac{x}{y}
sec\theta = \frac{1}{cos\theta}
csc\theta = \frac{1}{sin\theta}
Pythagorean Identities
The Pythagorean identity expresses the Pythagorean theorem in terms of trigonometric functions. It's a basic relation between the sine and cosine functions.
sin^2 \theta + cos^2 \theta = 1
There are more forms that are useful, but they can be derived from the above formula:
1 + tan^2\theta = sec^2\theta
cot^2 \theta + 1 = csc^2\theta
Even and Odd Identities
- A function is even if
f(-x) = f(x)
. - A function is odd if
f(-x) = -f(x)
- Cosine and secant are even
- Sine, tangent, cosecant, and cotangent are odd.
Examples
Even and Odd Functions
If
cot\theta = -\sqrt{3}
, what iscot(-\theta)
?
cot
is an odd function, and so cot(-\theta) = \sqrt{3}
Simplifying Using Identities
Simplify
\frac{sin\theta}{cos\theta}
- The above equation can be split into two components
\frac{sin\theta}{cos\theta} = \frac{sin\theta}{1} * \frac{1}{csc\theta}
- Referring to the list of trig identities, we know that
\frac{1}{csc\theta}
is equal tosin\theta
.
\frac{sin\theta}{1} * \frac{1}{csc\theta} = sin\theta * sin\theta
- Simplifying further, we get:
sin^2\theta
Finding all values using identities
If sec\theta = -\frac{25}{7}
and 0 < \theta < \pi
, find the values of the other 5 trig functions:
Using the trig identity 1 + tan^2\theta = cot^2\theta
, we can do this:
1 + tan^2\theta = (-\frac{25}{7})^2
$25^2