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Author SHA1 Message Date
zleyyij
d5b3c54761 vault backup: 2024-10-22 20:46:27 2024-10-22 20:46:27 -06:00
zleyyij
eb2fca5f2d vault backup: 2024-10-22 20:41:27 2024-10-22 20:41:27 -06:00

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Given the formula $\sin(\alpha + \beta)$: Given the formula $\sin(\alpha + \beta)$:
$$ \sin(\alpha + \beta) = \sin(\alpha)\cos(\beta) + \cos(\alpha)\sin(\beta) $$ $$ \sin(\alpha + \beta) = \sin(\alpha)\cos(\beta) + \cos(\alpha)\sin(\beta) $$
$$ \sin(\alpha - \beta) = \sin(\alpha)\cos(\beta) - \cos(\alpha)\sin(\beta) $$
Given the formula $\cos(\alpha + \beta)$: Given the formula $\cos(\alpha + \beta)$:
$$ \cos(\alpha + \beta) = \cos(\alpha)\cos(\beta) - \sin(\alpha)\sin(\beta) $$ $$ \cos(\alpha + \beta) = \cos(\alpha)\cos(\beta) - \sin(\alpha)\sin(\beta) $$
$$ \cos(\alpha - \beta) = \cos(\alpha)\cos(\beta) + \sin(\alpha)\sin(\beta) $$
Given the formula $\tan(\alpha + \beta)$:
$$\tan(\alpha + \beta) = \dfrac{\tan\alpha + \tan\beta}{1 - \tan\alpha\tan\beta} $$
$$\tan(\alpha - \beta) = \dfrac{\tan\alpha - \tan\beta}{1 + \tan\alpha\tan\beta} $$