vault backup: 2024-10-22 20:46:27
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Given the formula $\sin(\alpha + \beta)$:
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$$ \sin(\alpha + \beta) = \sin(\alpha)\cos(\beta) + \cos(\alpha)\sin(\beta) $$
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$$ \sin(\alpha - \beta) = \sin(\alpha)\cos(\beta) - \cos(\alpha)\sin(\beta) $$
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Given the formula $\cos(\alpha + \beta)$:
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$$ \cos(\alpha + \beta) = \cos(\alpha)\cos(\beta) - \sin(\alpha)\sin(\beta) $$
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$$ \cos(\alpha - \beta) = \cos(\alpha)\cos(\beta) + \sin(\alpha)\sin(\beta) $$
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Given the formula $\tan(\alpha + \beta)$:
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$$\frac{\alpha + \} \dfrac{\tan\alpha + \tan\beta}{1 - \tan\alpha\tan\beta} $$
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$$\tan(\alpha + \beta) = \dfrac{\tan\alpha + \tan\beta}{1 - \tan\alpha\tan\beta} $$
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$$\tan(\alpha - \beta) = \dfrac{\tan\alpha - \tan\beta}{1 + \tan\alpha\tan\beta} $$
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