arc/notes
1
0
Fork 0
Code Issues Pull Requests Actions Packages Projects Releases Wiki Activity

vault backup: 2025-03-06 09:14:22

Browse Source
This commit is contained in:
arc 2025-03-06 09:14:22 -07:00
parent 705bab4b9d
commit 773e850873
1 changed files with 2 additions and 1 deletions
Show Stats Download Patch File Download Diff File Expand all files Collapse all files

3
education/math/MATH1210 (calc 1)/Limits.md
View File

@ -82,6 +82,7 @@ If you have a limit of the indeterminate form $\dfrac{0}{0}$, the limit can be f
$$ \lim_{x \to 2} \dfrac{x-2}{x^2-4} = \lim_{x \to 2} \dfrac{1}{2x}$$ $$ \lim_{x \to 2} \dfrac{x-2}{x^2-4} = \lim_{x \to 2} \dfrac{1}{2x}$$
L'Hospital's Rule can also be used when both the numerator and denominator approach some form of infinity. L'Hospital's Rule can also be used when both the numerator and denominator approach some form of infinity.
$$ $$ $$ \lim_{x \to \infty} \dfrac{x^2-2}{3x^2-4} = \lim_{x \to \infty} \dfrac{2x}{6x}$$
The above problem can be solved more easily *without* L'Hospital's rule, the leading coefficients are 1/3, so the limit as $x$ approaches $\infty$ is 1/3.
L'Hospital's rule **cannot** be used in any other circumstance. L'Hospital's rule **cannot** be used in any other circumstance.