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education/math/MATH1210 (calc 1)/Limits.md

@@ -82,6 +82,7 @@ If you have a limit of the indeterminate form $\dfrac{0}{0}$, the limit can be f
 $$ \lim_{x \to 2} \dfrac{x-2}{x^2-4} = \lim_{x \to 2} \dfrac{1}{2x}$$
 
 L'Hospital's Rule can also be used when both the numerator and denominator approach some form of infinity.
-$$ $$
+$$ \lim_{x \to \infty} \dfrac{x^2-2}{3x^2-4} = \lim_{x \to \infty} \dfrac{2x}{6x}$$
+The above problem can be solved more easily *without* L'Hospital's rule, the leading coefficients are 1/3, so the limit as $x$ approaches $\infty$ is 1/3.
 
 L'Hospital's rule **cannot** be used in any other circumstance.