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education/math/MATH1060 (trig)/Identities.md
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@ -60,4 +60,9 @@ $cos\theta = -\frac{7}{25}$
3. To find $sin\theta$, we can use the trig identity $sin^2\theta + cos^2\theta = 1$: 3. To find $sin\theta$, we can use the trig identity $sin^2\theta + cos^2\theta = 1$:
$$ sin^2\theta + (-\frac{7}{25}) = 1 $$ $$ sin^2\theta + (-\frac{7}{25}) = 1 $$
Rearranging, we get: Rearranging, we get:
$$ 1 - (-\frac{7}{25} = sin^2\theta $$ $$ 1 - (-\frac{7}{25})^2 = sin^2\theta $$
Applying the exponent gives us $\frac{49}{625}$, so we can do this:
$$ \frac{625}{625} - \frac{49}{625} = \frac{576}{625} = sin^2\theta $$
Getting rid of the exponent:
$$ \sqrt{\frac{576}{625}} = $$