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education/math/MATH1210 (calc 1)/Integrals.md

@@ -107,7 +107,7 @@ This formula can also be stated as $\int_a^b f(x)dx = f(c)(b-a)$
 This theorem tells us that a continuous function on the closed interval will obtain its average for at least one point in the interval.
 
 # U-Substitution
-## Forumulas
+## Formulas
 - $\int k {du} = ku + C$
 - $\int u^n du = \frac{1}{n+1}u^{n+1} + C$
 - $\int \frac{1}{u} du = \ln(|u|) + C$ 
@@ -115,4 +115,5 @@ This theorem tells us that a continuous function on the closed interval will obt
 - $\int \sin(u) du = -\cos(u) + C$
 - $\int \cos(u) du = \sin(u) + C$
 - $\int \dfrac{1}{\sqrt{a^2 - u^2}} du = \arcsin(\frac{u}{a}) +C$ 
-- $\int \dfrac{1}{a^2+u^2}du = \dfrac{1}{a} \arctan(\frac{u}{a}) + C$  
+- $\int \dfrac{1}{a^2+u^2}du = \dfrac{1}{a} \arctan(\frac{u}{a}) + C$ 
+- $\int \dfrac{1}{u\sqrt{u^2 - a^2}} du = \dfrac{1}{a}arcsec(\dfrac{|u|}{a}) + C$