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education/math/MATH1210 (calc 1)/Integrals.md

@@ -13,6 +13,9 @@ $$ \int f(x) dx $$
 	1. Add 1 to the exponent
 	2. Multiply by $\dfrac{1}{n + 1}$
 3. This gives us an antiderivative of $\dfrac{1}{3}x^3$ 
+4. To check our work, work backwards.
+5. The derivative of $\dfrac{1}{3}x^3$ is $\dfrac{1}{3} (3x^2)$
+6. $= \dfrac{3}{3} x^2$
 
 
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