From 5646d57982e299ed2541b522c1fc824e07758948 Mon Sep 17 00:00:00 2001 From: arc Date: Thu, 20 Mar 2025 12:17:12 -0600 Subject: [PATCH] vault backup: 2025-03-20 12:17:12 --- education/math/MATH1210 (calc 1)/Integrals.md | 5 ++++- 1 file changed, 4 insertions(+), 1 deletion(-) diff --git a/education/math/MATH1210 (calc 1)/Integrals.md b/education/math/MATH1210 (calc 1)/Integrals.md index 3098345..e31096c 100644 --- a/education/math/MATH1210 (calc 1)/Integrals.md +++ b/education/math/MATH1210 (calc 1)/Integrals.md @@ -12,7 +12,10 @@ $$ \int f(x) dx $$ 2. To perform this operation in reverse: 1. Add 1 to the exponent 2. Multiply by $\dfrac{1}{n + 1}$ -3. This gives us an antiderivative of$\dfrac{1}{3}x^3$ +3. This gives us an antiderivative of $\dfrac{1}{3}x^3$ +4. To check our work, work backwards. +5. The derivative of $\dfrac{1}{3}x^3$ is $\dfrac{1}{3} (3x^2)$ +6. $= \dfrac{3}{3} x^2$ ## Formulas