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education/math/MATH1060 (trig)/Identities.md
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@ -51,4 +51,6 @@ Performing that subtraction gives us this:
$$ \frac{625}{49} - \frac{49}{49} = \frac{576}{49} = tan^2\theta $$ $$ \frac{625}{49} - \frac{49}{49} = \frac{576}{49} = tan^2\theta $$
You can get rid of the exponent: You can get rid of the exponent:
$$ \frac{576}{49} $$ \sqrt{\frac{576}{49}} = tan\theta $$
$\sqrt{576} = 24$ and $\sqrt{49} = 7$, so:
$$ tan\theta = \frac{24}{7} $$