JavaScript promise rejection: Loading CSS chunk katex failed. (error: https://git.47c.in/assets/css/katex.41d5cba5.css). Open browser console to see more details.
2023-12-15 09:30:09 -07:00

556 B

Examples

Given the below problem, the two equations can't simplified further. So to find the domain, you need to look for the domain where they're both valid, eg [-2, 5].

\sqrt{x+2} + \sqrt{5-x}

The below example has a domain of [-2, 5) because x cannot equal 0 for the denominator

\frac{\sqrt{x+2}}{\sqrt{5-x}}

Assuming f(x) = \frac{2}{x-3}, and g(x) = \frac{5}{x+1}, (f\circ g)(x), you can find the domain by finding the domain for each function, then fully expanding it and seeing if any more unreachable numbers are included