Given the formula $\sin(\alpha + \beta)$:
$$ \sin(\alpha + \beta) = \sin(\alpha)\cos(\beta) + \cos(\alpha)\sin(\beta) $$
Given the formula $\cos(\alpha + \beta)$:
$$ \cos(\alpha + \beta) = \cos(\alpha)\cos(\beta) - \sin(\alpha)\sin(\beta) $$
Given the formula $\tan(\alpha + \beta)$:
$$\frac{\alpha + \} \dfrac{\tan\alpha + \tan\beta}{1 - \tan\alpha\tan\beta} $$