diff --git a/education/math/Partial Fractions.md b/education/math/Partial Fractions.md
index bc8e56c..27d9594 100644
--- a/education/math/Partial Fractions.md	
+++ b/education/math/Partial Fractions.md	
@@ -4,7 +4,7 @@ This is the "main" method of solving, and the next two headings both focus on ge
 1. Factor the bottom. 
 2. Create two fractions, $\frac{a}{p1}$, and $\frac{b}{p2}$, where p1 and p2 are the polynomials you just factored out, and a/b are arbitrary variables
 3. Multiply a by p2, and b by p1., giving you: $$\frac{a*p2}{p1} + \frac{b*p1}{p2}$$
-4. When you split the 
+4. Now you can distribute $a$ and $b$, giving you $ax + c$ and $bx + d$. Group and factor. Your equation equals the original equation, so the numerator of the first equals $ax + bx + c + d$.
 
 ### Example
 $$ \frac{2x+1}{(x+1)(x+2)} $$
@@ -24,7 +24,10 @@ $$ 2x+1 = x(a + b) + (2a + b) $$
 7. With the above equation, each side is in the same form. it's $x$ multiplied by a constant ($2$ on the left, and $(a+b)$ on the right, and with a constant of $1$ on the left and $2a + b$) on the right, letting you find the two equations below:
 $$ 2 = a + b $$
 $$ 1 = 2a + b $$
-8. The above equations can be solved as a system of equations, giving you
+8. The above equations can be solved as a system of equations, giving you:
+$$ a=-1,\space b=3 $$
+9. Your answer would be:
+   $$ \frac{-1}{x+1} + \frac{3}{x+2} $$
 
 ## Degree of the numerator is equal
 1. First perform polynomial division.