From ef0ac61db54c1aa1171ffc96d14dc4ec44918da3 Mon Sep 17 00:00:00 2001
From: zleyyij <75810274+zleyyij@users.noreply.github.com>
Date: Mon, 7 Oct 2024 13:53:49 -0600
Subject: [PATCH] vault backup: 2024-10-07 13:53:48

---
 education/math/MATH1060 (trig)/Graphing.md | 3 ++-
 1 file changed, 2 insertions(+), 1 deletion(-)

diff --git a/education/math/MATH1060 (trig)/Graphing.md b/education/math/MATH1060 (trig)/Graphing.md
index fbbcf91..229851c 100644
--- a/education/math/MATH1060 (trig)/Graphing.md	
+++ b/education/math/MATH1060 (trig)/Graphing.md	
@@ -150,4 +150,5 @@ Vertical shift: $1$
 > Evaluate $\arccos{\frac{1}{2}}$ using the unit circle. 
 
 Taking the inverse of the above function, we get this. Because the domain of $cos$ ranges from $0$ to $\pi$ inclusive, the answer is going to be in quadrant 1 or quadrant 2. 
-$$ cos(x) = \frac{1}{2} $$
\ No newline at end of file
+$$ cos(a) = \frac{1}{2} $$
+When $x$ is equal to one half, the angle is equal to $\frac{\pi}{3}$. 
\ No newline at end of file