diff --git a/education/math/MATH1060 (trig)/Graphing.md b/education/math/MATH1060 (trig)/Graphing.md
index fbbcf91..229851c 100644
--- a/education/math/MATH1060 (trig)/Graphing.md	
+++ b/education/math/MATH1060 (trig)/Graphing.md	
@@ -150,4 +150,5 @@ Vertical shift: $1$
 > Evaluate $\arccos{\frac{1}{2}}$ using the unit circle. 
 
 Taking the inverse of the above function, we get this. Because the domain of $cos$ ranges from $0$ to $\pi$ inclusive, the answer is going to be in quadrant 1 or quadrant 2. 
-$$ cos(x) = \frac{1}{2} $$
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+$$ cos(a) = \frac{1}{2} $$
+When $x$ is equal to one half, the angle is equal to $\frac{\pi}{3}$. 
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