diff --git a/education/math/MATH1060 (trig)/Graphing.md b/education/math/MATH1060 (trig)/Graphing.md
index ced1392..fbbcf91 100644
--- a/education/math/MATH1060 (trig)/Graphing.md	
+++ b/education/math/MATH1060 (trig)/Graphing.md	
@@ -125,6 +125,8 @@ The inverse of a trig function is **not** the same as the reciprocal of a trig f
 - To find the inverse of cos, you need to restrict the domain to $[0, \pi]$
 - To find the inverse of tangent, you need to restrict the domain to $(-\frac{\pi}{2}, \frac{\pi}{2})$.
 
+The graphs of an inverse function can be found by taking the graph of $f$, and flipping it over the line $y=x$. 
+
 # Examples
 > Given $-2\tan(\pi*x + \pi) - 1$
 
@@ -145,3 +147,7 @@ Vertical shift: $1$
 | Period         | $\frac{\pi}{\|\pi\|} = 1$ |
 | Phase shift    | $\frac{-\pi}{\pi} = -1$   |
 | Vertical shift | $-1$                      |
+> Evaluate $\arccos{\frac{1}{2}}$ using the unit circle. 
+
+Taking the inverse of the above function, we get this. Because the domain of $cos$ ranges from $0$ to $\pi$ inclusive, the answer is going to be in quadrant 1 or quadrant 2. 
+$$ cos(x) = \frac{1}{2} $$
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