diff --git a/.obsidian/plugins/obsidian-git/data.json b/.obsidian/plugins/obsidian-git/data.json
index e69de29..bef4c6e 100644
--- a/.obsidian/plugins/obsidian-git/data.json
+++ b/.obsidian/plugins/obsidian-git/data.json
@@ -0,0 +1,27 @@
+{
+  "commitMessage": "vault backup: {{date}}",
+  "autoCommitMessage": "vault backup: {{date}}",
+  "commitDateFormat": "YYYY-MM-DD HH:mm:ss",
+  "autoSaveInterval": 5,
+  "autoPushInterval": 0,
+  "autoPullInterval": 5,
+  "autoPullOnBoot": true,
+  "disablePush": false,
+  "pullBeforePush": true,
+  "disablePopups": false,
+  "listChangedFilesInMessageBody": false,
+  "showStatusBar": true,
+  "updateSubmodules": false,
+  "syncMethod": "merge",
+  "customMessageOnAutoBackup": false,
+  "autoBackupAfterFileChange": false,
+  "treeStructure": false,
+  "refreshSourceControl": true,
+  "basePath": "",
+  "differentIntervalCommitAndPush": false,
+  "changedFilesInStatusBar": false,
+  "showedMobileNotice": true,
+  "refreshSourceControlTimer": 7000,
+  "showBranchStatusBar": true,
+  "setLastSaveToLastCommit": false
+}
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diff --git a/education/math/MATH1210 (calc 1)/Max and Min.md b/education/math/MATH1210 (calc 1)/Max and Min.md
index bc8c261..1c834c4 100644
--- a/education/math/MATH1210 (calc 1)/Max and Min.md	
+++ b/education/math/MATH1210 (calc 1)/Max and Min.md	
@@ -11,4 +11,14 @@ The absolute **minimum** is the smallest possible output value for a function.
 A number is considered critical if the output of a function exists and $\dfrac{d}{dx}$ is zero or undefined.
 
 # Local Max/Min
-A local max/min is a peak or trough at any point along the graph.
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+A local max/min is a peak or trough at any point along the graph.
+
+# Extreme Value Theorem
+If $f$ is a continuous function in a closed interval $[a, b]$, then $f$ achieves both an absolute maximum and an absolute minimum in $[a, b]$. Furthermore, the absolute extrema occur at $a$ or at $b$ or at a critical number between $a$ and $b$.
+
+## Example
+> Find the absolute maximum and absolute minimum of the function $f(x) = x^2 -3x + 2$ on the closed interval $[0, 2]$:
+1. $x=0$ and $x=2$ are both critical numbers because they are endpoints. Endpoints are *always* critical numbers because $\dfrac{d}{dx}$ is undefined.
+2. $\dfrac{d}{dx} x^2 -3x + 2 = 2x -3$
+3. Setting the derivative to zero, $0 = 2x - 3$
+4. Solving for x, we get $x = \dfrac{3}{2}$. Three halves is a critical number because $
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