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education/computer engineering/ECE1400/Chapter 5 Exercises.md

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+> 2. The following program fragments illustrate the logical operators. Show the output produced by each, assuming that `i`, `j`, and `k` are `int` variables.
+
+a. `i = 10; j = 5;`
+```c
+printf("%d", !i < j);
+
+// Expected output: `1`, because `!i` evaluates to 0, and 0 is less than 5, so that expression evaluates to true, or 1.
+```
+
+b. `i = 2; j = 1;`
+```c
+printf("%d", !!i + !j);
+
+// Expected output: `1`, because !!2 evaluates to 1, and !j evaluates to 0
+```
+
+c. `i = 5; j = 0; k = -5;`
+```c
+printf("%d", i && j || k);
+
+// Expected output: `1`, because i && j should evaluate to 0, but `0 || 1` should evalulate to true.
+```
+
+d. `i = 1; j = 2; k = 3;`
+```c
+printf("%d", i < j || k);
+
+// Expected output: `1`
+```
+
+> 4. Write a single expression whose value is either `-1`, `0`, or `1` depending on whether `i` is less than, equal to, or greater than `j`, respectively.
+
+```c
+/*
+	If i < j, the output should be -1.
+	If i == j, the output should be zero
+	If i > j, the output should be 1.
+*/
+(i > j) - (i < j)
+```
+
+> 6. Is the following `if` statement legal?
+```c
+if (n == 1-10)
+	printf("n is between 1 and 10\n");
+```
+
+Yes the statement is *legal*, but it does not produce the intended effect. It would not produce an output when `n = 5`, because `1-10` evaluates to `-9`, and `-9 != 5`.
+
+> 10. What output does the following program fragment produce? (Assume that `i` is an integer variable.)
+```c
+int i = 1;
+switch (i % 3) {
+	case 0: printf("zero");
+	case 1: printf("one");
+	case 2: printf("two");
+}
+```
+
+The program would print `onetwo` because each case is missing a `break` statement.
+
+> 11. The following table shows the telephone area codes in the state of Georgia along with the largest city in each area:
+
+| Area code | Major city |
+| --------- | ---------- |
+| 229       | Albany     |
+| 404       | Atlanta    |
+| 470       | Atlanta    |
+| 478       | Macon      |
+| 678       | Atlanta    |
+| 706       | Columbus   |
+| 762       | Columbus   |
+| 770       | Atlanta    |
+| 912       | Savannah   |
+> Write a switch statement whose controlling expression is the variable `area_code`. If the value of `area_code` is not in the table, the `switch` statement will print the corresponding city name. Otherwise, the `switch` statement will display the message `"Area code not recognized."` Use the techniques discussed in section 5.3 to make the `switch` as simple as possible.
+```c
+int area_code;
+
+switch (area_code) {
+	case 404:
+	case 470:
+	case 678:
+	case 770:
+		printf("Atlanta");
+		break;
+	case 706:
+	case 762:
+		printf("Columbus");
+		break;
+	case 229:
+		printf("Albany");
+		break;
+	case 478:
+		printf("Macon");
+		break;
+	case 912:
+		printf("Savannah");
+		break;
+	default:
+		printf("Area code not recognized.");
+		break;
+}
+```