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education/software development/ECE1400/Chapter.md

@@ -6,4 +6,19 @@ printf("%d", !i < j);
 
 // Expected output: `1`, because `!i` evaluates to 0, and 0 is less than 5, so that expression evaluates to true, or 1.
 ```
-b. `i = 2; j = `
+
+b. `i = 2; j = 1;`
+```c
+printf("%d", !!i + !j);
+
+// Expected output: `1`, because !!2 evaluates to 1, and !j evaluates to 0
+```
+
+c. `i = 5; j = 0; k = -5;`
+```c
+printf("%d", i && j || k);
+
+// Expected output: `1`, because i && j should evaluate to false, 
+```
+
+d. ``