diff --git a/education/math/MATH1210 (calc 1)/Integrals.md b/education/math/MATH1210 (calc 1)/Integrals.md
index 6e7c1c1..0c5328a 100644
--- a/education/math/MATH1210 (calc 1)/Integrals.md	
+++ b/education/math/MATH1210 (calc 1)/Integrals.md	
@@ -135,4 +135,12 @@ With a series of points on a curve we can find the distance between each point.
 As we increase $n$, the precision of which the curve is estimated increases.
 
 This means that:
-$$ len(curve) = \lim_{n \to \infty} \sum_{i=1}^{n}(\p{}$$
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+$$ \text{length of a curve} = \lim_{n \to \infty} \sum_{i=1}^{n}(\text{length of line segment)}$$
+Using the distance formula, we know that the length of the line segment can be found with:
+$$ \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} $$
+1. So the entire equation is:
+$$ \text{length of a curve} = \lim_{n \to \infty} \sum_{i=1}^{n}(\sqrt{(x_i - x_{i-1})^2 + (y_i - y_{i-1})^2}) $$
+	This can also be described as:
+$$ \text{length of a curve} = \lim_{n \to \infty} \sum_{i=1}^{n}(\sqrt{(\Delta x)^2 +(\Delta y)^2}) $$
+2. Using the mean value theorem:
+$$ \lim_{n \to \infty} \sum_{i = 1}^n) $$
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