diff --git a/.obsidian/plugins/obsidian-git/data.json b/.obsidian/plugins/obsidian-git/data.json
index 4bc189e..e69de29 100644
--- a/.obsidian/plugins/obsidian-git/data.json
+++ b/.obsidian/plugins/obsidian-git/data.json
@@ -1,27 +0,0 @@
-{
-  "commitMessage": "vault backup: {{date}}",
-  "autoCommitMessage": "vault backup: {{date}}",
-  "commitDateFormat": "YYYY-MM-DD HH:mm:ss",
-  "autoSaveInterval": 5,
-  "autoPushInterval": 0,
-  "autoPullInterval": 5,
-  "autoPullOnBoot": false,
-  "disablePush": false,
-  "pullBeforePush": true,
-  "disablePopups": false,
-  "listChangedFilesInMessageBody": false,
-  "showStatusBar": true,
-  "updateSubmodules": false,
-  "syncMethod": "merge",
-  "customMessageOnAutoBackup": false,
-  "autoBackupAfterFileChange": false,
-  "treeStructure": false,
-  "refreshSourceControl": true,
-  "basePath": "",
-  "differentIntervalCommitAndPush": false,
-  "changedFilesInStatusBar": false,
-  "showedMobileNotice": true,
-  "refreshSourceControlTimer": 7000,
-  "showBranchStatusBar": true,
-  "setLastSaveToLastCommit": false
-}
\ No newline at end of file
diff --git a/education/math/MATH1220 (calc II)/Sequences.md b/education/math/MATH1220 (calc II)/Sequences.md
index 576f129..e1bc0d3 100644
--- a/education/math/MATH1220 (calc II)/Sequences.md	
+++ b/education/math/MATH1220 (calc II)/Sequences.md	
@@ -111,5 +111,10 @@ Then if the *series converges* absolutely then the sum converges.
 
 > Does the series $\sum_{n=1}^\infty (\frac{(-1)^n}{n+5}$  conditionally converge, absolutely converge, or diverge?
 1. Consider $\sum_{n=1}^\infty|\frac{(-1)^n}{n+5}| = \sum_{n=1}^\infty \frac{1}{n+5}$.
-2. The above series can be compared to $\frac{1}{n}$ with the limit comparison test. 
+2. The above series can be compared to $\frac{1}{n}$ with the limit comparison test. $\lim_{n \to \infty}\dfrac{\frac{1}{n}}{\frac{1}{n+5}} = 1 \ne 0, \infty$. By the L.C.T, $\frac{1}{n+5}$ diverges, so the series does not absolutely converge.
+3. Applying the Alternating Series Test,
+	- $a_n > 0$ for all $n$ - all values in the series are greater than zero
+	- $a_n \ge a_{n+1}$ - the series decreases
+	- $\lim_{n \to \infty} a_n = 0$ - the series approaches zero
+All three conditions hold true, therefore we know that $\sum_{n=1}^\infty \frac{(-1)^n}{n+5}$ conditionally converges.