vault backup: 2023-12-15 09:30:09

education/math/Domain.md

@@ -4,4 +4,4 @@ Given the below problem, the two equations can't simplified further. So to find
 $$ \sqrt{x+2} + \sqrt{5-x} $$
 The below example has a domain of $[-2, 5)$ because $x$ cannot equal 0 for the denominator
 $$ \frac{\sqrt{x+2}}{\sqrt{5-x}} $$
-Assuming $f(x) = \frac{2}{x-3}$, 
+Assuming $f(x) = \frac{2}{x-3}$, and $g(x) = \frac{5}{x+1}$, $(f\circ g)(x)$, you can find the domain by finding the domain for each function, then fully expanding it and seeing if any more unreachable numbers are included