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education/math/MATH1060 (trig)/Graphing.md

@@ -76,11 +76,18 @@ Given the form $y = A\tan(Bx - C) + D$ (the same applies for $\cot$)
 - The vertical shift is $D$
 
 # Secant
-$$ y = \sec{x} $$
+$$ y = \sec(x) $$
 ![Graph of secant](assets/graphsec.jpg)
 
 $$ sec(x) = \frac{1}{\cos{x}} $$
-Because secant is the reciprocal of cosine, when $\cos{x} = 0$, then secant is undefined. $
+Because secant is the reciprocal of cosine, when $\cos{x} = 0$, then secant is undefined. $|\cos$| is never *greater than* 1, so secant is never *less than* 1 in absolute value. When the graph of cosine crosses the x axis, an asymptote for a matching graph of secant will appear there. 
+
+The general form of secant is:
+$$ y = A\sec(B{x} - C) + D $$
+$A$, $B$, $C$, and $D$ will have similar meanings to the secant functions as they did to the sine and cosine functions. 
+
+# Cosecant
+$$ y = \csc(x) $$
 
 # Examples
 > Given $-2\tan(\pi*x + \pi) - 1$