From 7dc4c3e1bc10cb56b189b8abba7015dabd91b811 Mon Sep 17 00:00:00 2001
From: arc <zleyyij@users.noreply.github.com>
Date: Wed, 3 Sep 2025 13:52:38 -0600
Subject: [PATCH] vault backup: 2025-09-03 13:52:38

---
 education/physics/PHYS2210/Unit 1.md | 21 +++++++++++++++++----
 1 file changed, 17 insertions(+), 4 deletions(-)

diff --git a/education/physics/PHYS2210/Unit 1.md b/education/physics/PHYS2210/Unit 1.md
index c19a618..30ab238 100644
--- a/education/physics/PHYS2210/Unit 1.md	
+++ b/education/physics/PHYS2210/Unit 1.md	
@@ -25,7 +25,20 @@ To find the instantaneous acceleration, we can apply the formula:
 
 $$a_{\text{instant}} = a = \frac{dv}{dt} = \frac{d}{dt} \frac{dx}{dt} = \frac{d^2x}{dt^2}$$
 ## Equations of Motion for Constant Acceleration
-1. $v = v_0 + at$ 
-2. $x = x_0 + \frac{1}{2}(v_0 + v)t$ 
-3. $x = x_0 + v_0 t + \frac{1}{2} a t^2$ 
-4. $v^2 = v_0^2 + 2a(x - x_0)$ 
+1. $v = v_0 + at$  - Use when missing $x$
+2. $x = x_0 + \frac{1}{2}(v_0 + v)t$  - Use when missing $a$
+3. $x = x_0 + v_0 t + \frac{1}{2} a t^2$  - Use when missing $v$
+4. $v^2 = v_0^2 + 2a(x - x_0)$  - Use when missing $t$ 
+
+
+Kinematics problems have a *start* and an *end* of the motion.
+
+| Initial        | Final |
+| -------------- | ----- |
+| $t_0$          | $t$   |
+| $v_0$          | $v$   |
+| $x_0$          | $x$   |
+| $a$ (constant) | $a$   |
+## Examples
+
+ > Sally aggressively drives her Alfa Romeo from rest to 50 m/s in 6s. What is her acceleration?