vault backup: 2024-02-14 09:15:34
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|  | Partial fraction decomposition is when you break a polynomial fraction down into smaller fractions that add together.  | ||||||
| ## Degree where the numerator is less | ## Degree where the numerator is less | ||||||
| 1. Factor the bottom.  | 1. Factor the bottom.  | ||||||
| 2. Create two fractions, a/p1, and b/p2, where p1 and p2 are the polynomials you just factored out, and a/b are arbitrary variables | 2. Create two fractions, $\frac{a}{p1}$, and $\frac{b}{p2}$, where p1 and p2 are the polynomials you just factored out, and a/b are arbitrary variables | ||||||
| 3. Multiply a by p2, and b by p1., giving you: $$\frac{a*p2}{p1} + \frac{b*p1}{p2}$$ | 3. Multiply a by p2, and b by p1., giving you: $$\frac{a*p2}{p1} + \frac{b*p1}{p2}$$ | ||||||
| 4. When you split the  | 4. When you split the  | ||||||
|  |  | ||||||
|  | ### Example | ||||||
|  | $$ \frac{2x+1}{(x+1)(x+2)} $$ | ||||||
|  | Given the above fraction, the denominator is already factored, so we can move onto the next step, where two fractions are made with $a$ and $b$ in the numerator, and each of the denominator components in the denominator: | ||||||
|  | $$ \frac{a}{x+1} + \frac{b}{x+2} $$ | ||||||
|  | Next, find a common denominator so that you can add the two fractions together. In this case, it's $(x+1)(x+2)$. | ||||||
|  |  | ||||||
| ## Degree of the numerator is equal | ## Degree of the numerator is equal | ||||||
| 1. First perform polynomial division. | 1. First perform polynomial division. | ||||||
| 2. Then find a partial fraction with the remainder | 2. Then find a partial fraction with the remainder | ||||||
|   | |||||||
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