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education/math/MATH1060 (trig)/Identities.md
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@ -36,4 +36,6 @@ $cot$ is an odd function, and so $cot(-\theta) = \sqrt{3}$
1. The above equation can be split into two components 1. The above equation can be split into two components
$$ \frac{sin\theta}{cos\theta} = \frac{sin\theta}{1} * \frac{1}{csc\theta} $$ $$ \frac{sin\theta}{cos\theta} = \frac{sin\theta}{1} * \frac{1}{csc\theta} $$
2. Referring to the list of trig identities, we know that $\frac{1}{csc\theta}$ is equal to $sin\theta$. 2. Referring to the list of trig identities, we know that $\frac{1}{csc\theta}$ is equal to $sin\theta$.
$$ \frac{sin\theta}{1} * \frac{1}{csc\theta} = sin\theta * sin\theta $$
3. Simplifying further, we get:
$$ sin^2\theta $$