diff --git a/education/math/MATH1220 (calc II)/Integral Review.md b/education/math/MATH1220 (calc II)/Integral Review.md
index 8962b58..6844735 100644
--- a/education/math/MATH1220 (calc II)/Integral Review.md	
+++ b/education/math/MATH1220 (calc II)/Integral Review.md	
@@ -14,6 +14,11 @@ Then let $f$ be a continous function on $[a, b]$ and let $F$ be the antiderivati
 Then $\int_a^b f(x) dx = F(b) - F(a)$.
 
 ## Examples
+1. Find the area under the curve between 0 and 1 of the function $f(x) = x^2$
 $$ \int_0^1 x^2 dx = \frac{1}{3} x^3 \Big |_0^1 = 1/3(1^3)- 1/3 (0)^3 = 1/3$$
-
-$$ \int_{-2}^2 2x + 2dx = \lim_{n \to \infty} \sum_{i = 1}^nf(x_i)\Delta x $$
\ No newline at end of file
+2. Find the Riemann Sum under the curve between -2 and 2 of the function $2x + 2$. 
+$$ \int_{-2}^2 (2x + 2)dx = \lim_{n \to \infty} \sum_{i = 1}^nf(x_i)\Delta x $$
+> Using the fact that $x_i = \Delta x + a$, $
+$$ = lim_{n \to \infty} \sum_{i=1}^n(2x_i + 2)\frac{4}{n}$$
+$$ = \lim_{n \to \infty} \sum_{i = 1}^n (2(-2 +\frac{4i}{n}) + 2)\frac{4}{n}$$
+$$ = \lim_{n \to \infty} \sum_{i = 1}^n(-4 + \frac{8i}{n} + 2)\frac{4}{n} $$
\ No newline at end of file