vault backup: 2026-02-09 19:20:04
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@@ -12,4 +12,5 @@ For the magnitude of a magnetic force:
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$$ |\vec(F_B)| = |q|vB\sin(\theta) $$
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For the radius of a particle's circular path:
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$$ r = \frac{mv}{qB} $$For the period of a particle's circular orbit in a uniform magnetic field:
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$$
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$$ T = \frac{2\pi r}{v} = \frac{2\pi}{v}\frac{mv}{qB} = \frac{2\pi m}{qB} $$
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- The period is independent of the particle's speed and orbital radius.
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