vault backup: 2025-04-17 09:05:41
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@ -193,4 +193,6 @@ $$ L =\int_a^b \sqrt{1 + f'(x)^2} dx$$
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> Set up an integral to find the length of the curve $y = \sin(x)$ from the point $(0, 0)$ to the point $(2\pi, 0)$.
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1. $L = \int_0^{2\pi} \sqrt{1 + \cos^2{x}}dx$ : The derivative of $\sin$ is $\cos$
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2. Plug into calculator
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2. Plug into calculator
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# Area Between Curves
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