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education/math/MATH1060 (trig)/Identities.md
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@ -55,4 +55,9 @@ $$ \sqrt{\frac{576}{49}} = tan\theta $$
$\sqrt{576} = 24$ and $\sqrt{49} = 7$, so: $\sqrt{576} = 24$ and $\sqrt{49} = 7$, so:
$$ tan\theta = \frac{24}{7} $$ $$ tan\theta = \frac{24}{7} $$
2. To find $cos\theta$, because $sec$ is the inverse of $cos$, we can use the identity $sec\theta = \frac{1}{cos\theta}$: 2. To find $cos\theta$, because $sec$ is the inverse of $cos$, we can use the identity $sec\theta = \frac{1}{cos\theta}$:
So $cos\theta = -\frac{7}{25}$. $cos\theta = -\frac{7}{25}$
3. To find $sin\theta$, we can use the trig identity $sin^2\theta + cos^2\theta = 1$:
$$ sin^2\theta + (-\frac{7}{25}) = 1 $$
Rearranging, we get:
$$ 1 - (-\frac{7}{25} = sin^2\theta $$