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education/math/Quadratics.md
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@ -5,7 +5,7 @@ $$ y = -5x^2 -20x + 13 $$
Given the above equation, you can factor out a -5, resulting in the equation $-5(x^2+4x) + 13)$. Half of 4 is 2, and because the inside is multiplied by -5, $-5 *4 = -20$, so you add -20 to the other side to equalize the equation, resulting in an equation in the form of $-20 + y = -5(x+2)^2+ 13$. This simplifies down to $y = -5(x+2)^2 + 33$.
# Forms
**Standard form (vertex form)**
$$ a(x - h)^2 + k $$
$$ y = a(x - h)^2 + k $$
To convert to standard form given a vertex of a quadratic equation and a point that falls along that line, plug values in for everything and solve for $a$.
**Quadratic form**