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vault backup: 2024-02-05 10:18:02

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zleyyij 2024-02-05 10:18:02 -07:00
parent c713e7c577
commit 0e5c3f1474
2 changed files with 4 additions and 2 deletions
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2
.obsidian/plugins/obsidian-git/data.json vendored
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@ -2,7 +2,7 @@
"commitMessage": "vault backup: {{date}}", "commitMessage": "vault backup: {{date}}",
"autoCommitMessage": "vault backup: {{date}}", "autoCommitMessage": "vault backup: {{date}}",
"commitDateFormat": "YYYY-MM-DD HH:mm:ss", "commitDateFormat": "YYYY-MM-DD HH:mm:ss",
"autoSaveInterval": 1, "autoSaveInterval": 5,
"autoPushInterval": 0, "autoPushInterval": 0,
"autoPullInterval": 5, "autoPullInterval": 5,
"autoPullOnBoot": false, "autoPullOnBoot": false,

4
education/math/Systems of Equations.md
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@ -25,4 +25,6 @@ $$ 4x -3y = -13 $$
You "add" the two equations together, getting: You "add" the two equations together, getting:
$$ 6x + 0y = 10 $$ $$ 6x + 0y = 10 $$
You now know that $6x = 10$. You now know that $6x = 10$.
If you don't have two values that evenly cancel out, like $3$ and $-4$, you can find the least common multiple and multiply the entire equation so that those two are equal. In this case, you'd multiply one equation by 4, and one equation by 3. If the signs don't cancel out, you can multiply one of the equations by -1. If you don't have two values that evenly cancel out, like $3$ and $-4$, you can find the least common multiple and multiply the entire equation so that those two are equal. In this case, you'd multiply one equation by 4, and one equation by 3. If the signs don't cancel out, you can multiply one of the equations by -1.
If given systems of equations with 3 variables, you pick two equations, and eliminate one variable from them. Then you pick one of the first two equations, and the last equation, and eliminate that same variable from them. This will give you two different equations that only have two variables. You can then use elimination again, and solve for one variable. This allows you to solve the rest of the equation