From 0ac24032c0a2706db6d5f6387dd2f7f761548eac Mon Sep 17 00:00:00 2001
From: zleyyij <75810274+zleyyij@users.noreply.github.com>
Date: Wed, 18 Sep 2024 11:42:12 -0600
Subject: [PATCH] vault backup: 2024-09-18 11:42:12

---
 .../software development/ECE1400/Chapter.md   | 20 ++++++++++++++++---
 1 file changed, 17 insertions(+), 3 deletions(-)

diff --git a/education/software development/ECE1400/Chapter.md b/education/software development/ECE1400/Chapter.md
index d8e024d..2183477 100644
--- a/education/software development/ECE1400/Chapter.md	
+++ b/education/software development/ECE1400/Chapter.md	
@@ -40,9 +40,23 @@ printf("%d", i < j || k);
 ```
 
 > 6. Is the following `if` statement legal?
-
 ```c
-if (n >= 1 <= 10)
+if (n == 1-10)
 	printf("n is between 1 and 10\n");
 ```
-Yes the statement is *legal*, but it does not produce the intended effect. It would produce an output when `n` is zero because `0 >= 1` would evaluate to `0`, and `0 <= 10` is false.
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+
+Yes the statement is *legal*, but it does not produce the intended effect. It would not produce an output when `n = 5`, because `1-10` evaluates to `-9`, and `-9 != 5`.
+
+> 10. What output does the following program fragment produce? (Assume that `i` is an integer variable.)
+```c
+int i = 1;
+switch (i % 3) {
+	case 0: printf("zero");
+	case 1: printf("one");
+	case 2: printf("two");
+}
+```
+
+The program would print `onetwo` because each case is missing a `break` statement.
+
+> 11. The following table shows the telephone ar
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