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@@ -147,4 +147,9 @@ The behavior a given power series falls into one of three cases:
$$ \frac{x}{3}$$ $$ \frac{x}{3}$$
2. For a geometric series, it converges when the ratio $r$ is less than one. Written as an equality, this gives us: 2. For a geometric series, it converges when the ratio $r$ is less than one. Written as an equality, this gives us:
$$ |r| < 1 \to |\frac{x}{3}| < 1 \to |x| < 3 $$ $$ |r| < 1 \to |\frac{x}{3}| < 1 \to |x| < 3 $$
This means that the interval of convergence is $(-3, 3)$, given it diverges at both interval endpoints. This means that the interval of convergence is $(-3, 3)$, given it diverges at both interval endpoints.
## Integral test for series
The integral test determines if an infinite series converges or diverges by comparing it to an improper integral. If the integral diverges ($= \infty$), then the series also diverges. If the integral converges, then the series is
Given the series $\sum_{n=0}^\infty a_n$, the improper integral would be of the below form: