notes/education/software development/ECE1400/Chapter 9 Exercises.md

78 lines
2.0 KiB
Markdown
Raw Permalink Normal View History

2024-10-13 02:37:02 +00:00
> 1. The following function, which computes the area of a triangle, contains two errors. Locate the errors and show how to fix them. (*Hint*: There are no errors in the formula)
```c
2024-10-13 02:42:02 +00:00
double triangle_area(double base, height)
double product;
{
product = base * height;
return product / 2;
}
```
2024-10-13 02:37:02 +00:00
2024-10-13 02:42:02 +00:00
Answer:
```c
// A type annotation is needed for `height`
double triangle_area(double base, double height)
{
// The `product` variable declaration was not in the function block.
double product;
product = base * height;
return product / 2;
}
```
> 2. Write a function `check(x, y, n)` that returns `1` if both `x` and `y` fall between zero and `n - 1` inclusive. The function should return 0 otherwise. Assume that `x`, `y`, and `n` are all of type int
```c
int check(int x, int y, int n) {
2024-10-13 02:47:02 +00:00
int in_range = 1;
if (x < 0 || y < 0) {
in_range = 0;
}
if (x > n - 1 || y > n - 1) {
in_range = 0;
}
return in_range;
2024-10-13 02:42:02 +00:00
}
2024-10-13 02:47:02 +00:00
```
> 7. Suppose that function `f` has the following definition:
> `int f(int a, int b) { ... }`
> Which of the following statements are legal? Assume that `i` has type `int` and `x` has type `double`).
2024-10-13 02:52:02 +00:00
Answer:
All of them are legal and will compile and run. (c) and (d) are what I would consider bad practice because they perform an implicit conversion from a double to an int, and should include an explicit cast.
> 8. Which of the following would be valid prototypes for a function that returns nothing and has one double parameter?
Answer:
(a) and (b).
2024-10-13 02:57:02 +00:00
Parameters must contain a type annotation but they do not need to specify a name. A function prototype declaration must specify a return type.
> 9. What will be the output of the following program?
```c
2024-10-13 03:02:02 +00:00
#include <stdio.h>
void swap (int a, int b);
int main(void)
2024-10-13 02:57:02 +00:00
{
2024-10-13 03:02:02 +00:00
int i = 1, j = 2;
swap(i, j);
printf("i = %d, j = %d\n", i, j);
return 0;
2024-10-13 02:57:02 +00:00
}
2024-10-13 03:02:02 +00:00
void swap(int a, int b)
2024-10-13 02:57:02 +00:00
{
2024-10-13 03:02:02 +00:00
int temp = a;
a = b;
b = temp;
2024-10-13 02:57:02 +00:00
}
```
2024-10-13 03:02:02 +00:00
Answer:
```
i = 1, j = 2
```
Because function parameters are passed by value and not reference in C, modifications to `a` and `b` are limited to the scope of `swap`.